2[x-(2x+8)+5]=2(k+3)

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Solution for 2[x-(2x+8)+5]=2(k+3) equation:


Simplifying
2[x + -1(2x + 8) + 5] = 2(k + 3)

Reorder the terms:
2[x + -1(8 + 2x) + 5] = 2(k + 3)
2[x + (8 * -1 + 2x * -1) + 5] = 2(k + 3)
2[x + (-8 + -2x) + 5] = 2(k + 3)

Reorder the terms:
2[-8 + 5 + x + -2x] = 2(k + 3)

Combine like terms: -8 + 5 = -3
2[-3 + x + -2x] = 2(k + 3)

Combine like terms: x + -2x = -1x
2[-3 + -1x] = 2(k + 3)
[-3 * 2 + -1x * 2] = 2(k + 3)
[-6 + -2x] = 2(k + 3)

Reorder the terms:
-6 + -2x = 2(3 + k)
-6 + -2x = (3 * 2 + k * 2)
-6 + -2x = (6 + 2k)

Solving
-6 + -2x = 6 + 2k

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -2x = 6 + 6 + 2k

Combine like terms: -6 + 6 = 0
0 + -2x = 6 + 6 + 2k
-2x = 6 + 6 + 2k

Combine like terms: 6 + 6 = 12
-2x = 12 + 2k

Divide each side by '-2'.
x = -6 + -1k

Simplifying
x = -6 + -1k

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